【数学分式计算,要过程】 (a²-4)分之2a-(a-2)分之1 (x-3)分之1...
发布网友
发布时间：2024-10-24 09:54
共1个回答
热心网友
时间：2024-11-16 12:05
（a²-4）分之2a-（a-2）分之1
=2a/(a+2)(a-2)-(a+2)/(a+2)(a-2)
=(2a-a-2)/(a+2)(a-2)
=(a-2)/(a+2)(a-2)
=1/(a+2)
（x-3）分之1-（x+3）分之1
=(x+3)/(x+3)(x-3)-(x-3)/(x+3)(x-3)
=(x+3-x+3)/(x+3)(x-3)
=6/(x²-9)
（a²-4a+4）分之（a-1）÷（a²-4）分之（a²-1）
=(a-1)/(a-2)²×(a+2)(a-2)/(a+1)(a-1)
=(a+2)/(a-2)(a+1)
=(a+2)/(a²-a-2)
【（x-2）分之3x-（x+2）分之x】×x分之（x²-4）
=[3x/(x-2)-x/(x+2)]×(x+2)(x-2)/x
=3(x+2)-(x-2)
=3x+6-x+2
=2x+8
热心网友
时间：2024-11-16 12:06
（a²-4）分之2a-（a-2）分之1
=2a/(a+2)(a-2)-(a+2)/(a+2)(a-2)
=(2a-a-2)/(a+2)(a-2)
=(a-2)/(a+2)(a-2)
=1/(a+2)
（x-3）分之1-（x+3）分之1
=(x+3)/(x+3)(x-3)-(x-3)/(x+3)(x-3)
=(x+3-x+3)/(x+3)(x-3)
=6/(x²-9)
（a²-4a+4）分之（a-1）÷（a²-4）分之（a²-1）
=(a-1)/(a-2)²×(a+2)(a-2)/(a+1)(a-1)
=(a+2)/(a-2)(a+1)
=(a+2)/(a²-a-2)
【（x-2）分之3x-（x+2）分之x】×x分之（x²-4）
=[3x/(x-2)-x/(x+2)]×(x+2)(x-2)/x
=3(x+2)-(x-2)
=3x+6-x+2
=2x+8
